Question

if alpha,beeta are the roots of 6x^2+4root2x-3=0 then alpha^2beeta+alphabeeta^2

Answer 1

Answer:

$\frac{ \sqrt{2} }{3}$

Step-by-step explanation:

${ \alpha }^{2} \beta + \alpha { \beta}^{2} \\ = \alpha \beta ( \alpha + \beta ) \\ = \frac{c}{a} ( - \frac{b}{a} ) \\ = \frac{ - 3}{6} ( \frac{ - 4 \sqrt{2} }{6} ) \\ = \frac{ \sqrt{2} }{3}$