Question

if alpha,beeta are the zeroes of the polynomial x²-2x-15,then form a quadratic polynomial whose zeroes are 2alpha and 2beeta

Answer 1

Given equation :-

x² - 2x - 15

x² - 5x + 3x - 15

x ( x - 5 ) + 3 ( x - 5 )

( x + 3 ) ( x - 5 )


• ( x + 3 ) = 0

x = - 3

• ( x - 5 ) = 0

x = 5


Let alpha be - 3
and beta be 5


So the zeros of another polynomial is :-

° 2 alpha :- 2 × - 3 = - 6

° 2 beta :- 2 × 5 = 10


As we know that to form a quadratic equation we have a formula that is

${x}^{2} - (sum \: o f \: zeros)x + (product \: of \: zeros \: )$

So,

Sum of zeros :-

- 6 + 10 = 4

Product of zeros :-

- 6 × 10 = - 60


Now putting the value in the formula.

x² - 4x - 60

Answer 2

Answer:

I don't know how

Step-by-step explanation:

tumhe nhi ata to teacher se pucho saalo ispr Kya dekh the ho