Question

If alpha+beeta are the zeros of 7x^2-19x-6,Find​

Answer 1

7x²-19x-6

7x²-21x+2x-6

7x(x-3)+2(x-3)

7x+2,x-3

7x+2=0,x-3=0

7x=-2,x=3

x=-2/7,x=3

(alpha²+beta²)=(alpha+beta)²-2alpha *beta. =(-2)²-2*-2/7

=4 -14-2/7

=4-16/7

=-12/7