if alpha-beta,alpha,alpha+beta are zeros of x3-6x2+8x, then find the value of beta
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Alpha plus beta plus gama is equal to minus b upon a by this we can find out the value of alpha and from other theorm we can find out beta
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Answer:
β = ±2
Step-by-step explanation:
The equation is given to be : x³ - 6x² + 8x
The zeros of the given equation are : α - β , α , α + β
Now, a = 1 , b = -6 , c = 8 , d = 0
Now, sum of all zeros = -b/a
⇒ α - β + α + α + β = 6
⇒ 3·α = 6
⇒ α = 2
Also, The product of zeros = d/a
⇒ (α - β) × (α) × (α + β) = 0
⇒ α² - β² = 0
⇒ β² = α²
⇒ β² = 4
⇒ β = ±2
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