Math, asked by jasmeetsidhu1, 1 year ago

if alpha-beta,alpha,alpha+beta are zeros of x3-6x2+8x, then find the value of beta

Attachments:

Answers

Answered by shalinikaushik999
42

This is answer

Alpha plus beta plus gama is equal to minus b upon a by this we can find out the value of alpha and from other theorm we can find out beta



Attachments:
Answered by throwdolbeau
52

Answer:

β = ±2

Step-by-step explanation:

The equation is given to be : x³ - 6x² + 8x

The zeros of the given equation are : α - β , α , α + β

Now, a = 1 , b = -6 , c = 8 , d = 0

Now, sum of all zeros = -b/a

⇒ α - β + α + α + β = 6

⇒ 3·α = 6

⇒ α = 2

Also, The product of zeros = d/a

⇒ (α - β) × (α) × (α + β) = 0

⇒ α² - β² = 0

⇒ β² = α²

⇒ β² = 4

⇒ β = ±2

Similar questions