if alpha+beta = alpha beta is zero of kx²-2x+k find k
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2/3
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If α,β are the zeros of kx
2
−2x+3k such that α+β=αβ then k=?
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Correct option is
C
3
2
Given α,β are the zeros of kx
2
−2x+3k
As we know that
Sum and product of zeros of ax
2
+bx+c is −
a
b
,
a
c
respectively
Given α+β=αβ
⟹
k
2
=
k
3k
⟹
k
2
=3
⟹k=
3
2
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