Math, asked by suryaboss6487, 10 months ago

If alpha beta and gama are the zeroes of polynomial ax^3+bx^2+cx+d then
1/alpha+1/beta+1/gamma is

Answers

Answered by zahaansajid
10

Good Morning

How r u?? ❤️

Here's your answer

If α, β, γ are the zeroes of the polynomial p(x) = ax³+bx²+cx+d then,

α+β+γ = -b/a

αβ+βγ+γα = c/a

αβγ = -d/a

1/α + 1/β + 1/γ

= (βγ+αγ+αβ) / αβγ

= (c/a) / (-d/a)

= -c/d

Hope this is helpful to you

Pls mark as brainliest

Follow me and I'll follow you back

Similar questions