If alpha, beta and gama are the zeroes of the cubic ax cube + bx square + 5x +3, then find the value of alpha ×beta +beta ×gama +gama ×alpha. The answer is 5/a. But I don't know how to calculate this .
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so here ir ur answer
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studentA:
Thank you a lot .
ur welcome
c=5, a=?
a =a
because the equation is ax3 + bx2+5x+3 and the x3 coefficient is a
Please tell me, why you don't take b . You take only a and c . please tell me.
because the formula is c divided by a
that is constant term divided by x3 term that is the reason
OK Thank you again.
no problm....
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