Question

if alpha beta and Gama are zeroes at p(x)=1/2x^3-5x^2-11x-3 then alpha+beta+gama=​

Answer 1

Answer:

α+β+γ=10

Step-by-step explanation:

if α,β,γ are zeroes of ax³+bx²+ cx +d

Then α+β+γ=-b/a

p(x) = 1/2x³-5x²-11x-3 then

a=1/2 and b=-5

so α+β+γ= -(-5)/(1/2)

=5*2=10