Question

If alpha beta and gamma are the roots of the equation x3+x2-x+8 find alpha^-1+beta^-1+ gamma^-1

Answer 1

Answer:

1/8

Step-by-step explanation:

x3+x2-x+8 = 0

∝ + β + g = -1

∝β + ∝g + bg = -1

∝βg = -8

alpha^-1+beta^-1+ gamma^-1

= 1/∝ + 1/β + 1/g = (∝β + ∝g + bg)/∝βg = -1/-8 = 1/8