if alpha,beta and gamma are the zeroes of cubic polynomial kx3-5x+9 and alpha3 + beta3+ gamma3=27, then find the value of k
BrainlyDarwin:
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hey dear ☺☺❤
Ur answer is here
____________________________________
=> 3a+ 3ß + 3 gama = 27
=> 3( a+ß + gama = 27/3 = 9
now we no that,
:-> a + ß + gama = - coefficient of x
square/ coefficient of x cube
= > 9 = -0/k
= > 9 k = 0
= > k = 0
hope it's help uuu ☺❤
Sumit## ^_-
Ur answer is here
____________________________________
=> 3a+ 3ß + 3 gama = 27
=> 3( a+ß + gama = 27/3 = 9
now we no that,
:-> a + ß + gama = - coefficient of x
square/ coefficient of x cube
= > 9 = -0/k
= > 9 k = 0
= > k = 0
hope it's help uuu ☺❤
Sumit## ^_-
Hiii
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