If alpha, beta and gamma are the zeroes of the polynomial 2x3 – 2x2 + 3x – 4, then evaluate alpha/beta gamma + beta / gamma alpha + gamma/alpha beta
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Correct option is
B
−3
we have to find,αβγ
Now,From the given Equation:2x³+x²−13x+6=0, Where,a=2,b=1,c=(−13),d=6
we know that:−α+β+γ=−ab=−21
αβγ=−ad=−26=−3
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