Question

if alpha beta and gamma are the zeros of 2 x cube minus 4 x square + 5 x + 6 then find the value of
1 alpha + beta + Gamma
2 Alpha Bita + Bita Gama + gama alpha
3 alpha beta gamma​

Answer 1

Step-by-step explanation:

2x³-4x²+5x+6

1.alpha+beta+gamma= -b/a

=-(-4)/2 =2

2.c/a = 5/2

3 -d/a = -6/2= -3

here a is cofficient of x³,

b is cofficient of x ²

c is cofficient of x

d is constant

Answer 2

Answer:

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Step-by-step explanation:

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