if alpha beta and gamma are the zeros of the cubic polynomial PX equal to 3 x cube - 6 X square + 5 x minus 3 then find their sum and product
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sum of alpha,beta,gamma= -b/a
= -(-6)/3
= 6/3 =2
Product of alpha,beta,gamma= d/a
= 3/3
= 1
= -(-6)/3
= 6/3 =2
Product of alpha,beta,gamma= d/a
= 3/3
= 1
Answered by
20
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