If alpha , beta are the roots of 2x²-4x+5=0 the 1/alpha+1/beta is
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Given: α,β are the roots of the equation 2x
2
+4x−5=0
To find the equation whose roots are the reciprocals of 2α−3,2β−3
Sol: From the given criteria, x=α,β
Let y=2x−3⟹x=
2
y+3
Now put value of x in the given equation, we get
2(
2
y+3
)
2
+4(
2
y+3
)−5=0
⟹2(y
2
+6x+9)+8y+24−20=0×4
⟹2y
2
+20y−22=0
⟹y
2
+10y−11=0
i.e., the equation whose roots are the reciprocals of 2α−3,2β−3 is x
2
+10x−11=0
Step-by-step explanation:
Hope it will be helpful.
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