If alpha, beta are the roots of the equation 2x ^ 2 + x - 6 = 0 , then the equation whose roots ar * e ^ (1/a) * a * n * d ^ (1/beta)
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Answer:
Correct option is
C
4x
2
−49x+118=0
α+β=
2
3
And
α.β=−3
Therefore,
α
2
+β
2
=(α+β)
2
−2αβ
=
4
9
+6
=
4
33
Hence, the equation will be
x
2
−(
4
33
+4)x+(9+2(
4
33
+4)=0
4x
2
−49x+118=0.
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