if alpha, beta are the roots of x^2+ bx + c then find Alpha power 5 + beta power 5
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α⁵+β⁵ = -b⁵ + 5cb³ - 5bc²
Step-by-step explanation:
(α³+β³)(α²+β²) = α⁵+β⁵ + α²β²(α+β)
=> α⁵+β⁵ = (α³+β³)(α²+β²) - α²β²(α+β)
=> α⁵+β⁵ = (α+β)(α²+β² - αβ)(α²+β²) - (αβ)²(α+β)
=> α⁵+β⁵ = (α+β)(α²+β² - αβ)((α+β)² - 2αβ) - (αβ)²(α+β)
=> α⁵+β⁵ = (α+β)((α+β)²- 3αβ)((α+β)² - 2αβ) - (αβ)²(α+β)
α+β = - b
αβ = c
=> α⁵+β⁵ = (-b)(b²- 3c)(b² - 2c) - (c)²(-b)
=> α⁵+β⁵ = (-b) ( (b²- 3c)(b² - 2c) - (c)²)
=> α⁵+β⁵ = (-b) ( b⁴ - 5cb² + 6c² - c²)
=> α⁵+β⁵ = (-b) ( b⁴ - 5cb² + 5c²)
=> α⁵+β⁵ = -b⁵ + 5cb³ - 5bc²
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