if alpha beta are the roots of x^3-2x^2 +3x-4=0 then find( 1)sumation r^2 beta2
(2)sumation r beta(alpha+beta)
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1
Answer:
-7
Step-by-step explanation:
x3 – 2x2 + 3x – 4 = 0
α + β + γ = 2
αβ + βγ + γα = 3
α β γ = 4
α2β2 + β2 γ2 + γ2 α2 = (αβ + βγ + γα)2 – 2 α β γ (α + β + γ)
= 32 – 2 * 4 (2)
= 9 – 16
= – 7
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