Question

if alpha, beta are the roots of x square + bx + c is equals to zero then one by Alpha cube plus one by beta cube is equals to​

Answer 1

Step-by-step explanation:

1. when we solve this problem
2. we get the value of α andβ
3. then take cube of α's value
4. and with β
5. and we get the values

Answer 2

Answer:

=   3cb - b^2 / c^3

Step-by-step explanation:

sum of zeroes = - B/A =  alpha + beta = -b/1  

product of zeroes = C/A = (alpha)(beta) = c/1

to find

1 / alpha^3  + 1/beta^3

=  alpha^3 + beta^3/ alpha^3 beta^3  [ a^3 + b^3 = (a+b)( a^2 + b^2 -ab )]

= ( alpha + beta)(alpha^2 + beta^2 - alpha beta) / (alpha beta)^3

= ( -b/1) ( ( alpha + beta)^2 - 2alpha beta - alpha beta)) / (c/1)^3  [ a^2 + b^2 =                                                                                                        

                                                                                                          (a+b)^2 - 2ab }

putting the values we get

=   3cb - b^2 / c^3

plz.................brainliest