Question

if alpha, beta are the roots of x square + bx + c is equals to zero, then find the equation whose roots are alpha + 2 ,Beta + 2​

Answer 1

if roots are alpha + 2 & beta +2

(x-(alpha+2))(x-(beta +2))=0

x^2 - ×(alpha + beta +4) +(alphabeta + 2(alpha+beta) +4 ) = 0

while

(x-alpha)(x-beta) = 0

x^2 - x (alpha+ beta) + alphabeta = 0

comparing with

x^2 + bx + c

alpha + beta = -b

alphabeta = c

putting these values

x^2 -×(-b+4) +(c + 2(-b) +4) = 0

x^2 + x(b-4) -2b + c + 4 = 0

Answer 2

Answer:

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