Question

If alpha, beta are the zeroes of polynomial 25 p^2-15 p +12,then find the of alpha^-1 + beta^-1 + gamma^-1​

Answer 1

Answer:  

$We have,Polynomial 25p2−15p+2On comparing that,Ap2+Bp+CThen,A=25,B=−15,C=2Given that,Sum of roots=α+β=A−Bα+β=2515α+β=53Product of rootsα.β=ACα.β=252Now,2α1and2β1Then,Sum of roots2α1+2β1=4αβ2α+2β=24αβ(α+β)=2αβ(α+β)=252×253=53×425=4152α1+2β1=415Product of roots=2α1×2β1=4αβ1=254×21=825So, the equation of polynomial isp2−(Sumofroots)p+productofroots⇒p2−415p+825⇒88p2−30p+25$

or and also check the attachment

Step-by-step explanation: