Question

If alpha,beta are the zeroes of px^2-2x+3q and alpha+beta=alpha×beta find p​

Answer 1

Answer:

$\frac{2}{3}$

Step-by-step explanation:

$p(x) = p {x}^{2} - 2x + 3q \\ \alpha + \beta = \alpha \beta \\ \alpha + \beta = \frac{ - b}{a} = \frac{ 2}{p} \\ \alpha \beta = \frac{c}{a} = \frac{3q}{p} \\ \frac{2}{p} = \frac{3q}{p} \\ q = \frac{2}{3}$