If alpha,beta are the zeroes of quadratic polynomial ax²+bx+c find the value of alpha³+beta³
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★ QUADRATIC RESOLUTION ★
GIVEN EQUATION : ax² + bx + c = 0
Acquired roots are ; [α , β]
α³ + β³ = (α + β)³ - 3αβ (α + β)
= (-b/a)³ - 3( c/a ) ( - b / a )
= -b³/ a³ + bc / a²
= -b³ + abc / a³
= abc - b³ / a³
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GIVEN EQUATION : ax² + bx + c = 0
Acquired roots are ; [α , β]
α³ + β³ = (α + β)³ - 3αβ (α + β)
= (-b/a)³ - 3( c/a ) ( - b / a )
= -b³/ a³ + bc / a²
= -b³ + abc / a³
= abc - b³ / a³
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