Question

If ,alpha, beta are the zeroes of the polynomial


kx^2 − 2x + 3k such that alpha + beta = alpha*beta , then find the


value of k. answer fast

Answer 1

Step-by-step explanation:

Given that α,βα,β are zeros of kx2 – 2x + 3k such that α+βα+β = αβαβ. Since, α & β are zeros of kx2 – 2x + 3k. Therefore, sum of zeros = α+βα+β = −ba−ba = −(−2)k−(−2)k = 2k2k. (In kx2 – 2x + 3k, a = k, b = –2, c = 3k) & product of zeros α,βα,β = ca=3kk=3ca=3kk=3. Now, given that α+βα+β = αβαβ ⇒ 2k2k = 3. Hence, k = 2/3

Answer 2

The value of k=1 by solving its correct