Question

if alpha, beta are the zeroes of the polynomial p[x} = x2-p[x+1]-c such that [alpha+1][beta+1]=0.what is the value of c?

Answer 1

Step-by-step explanation:

p(x)

$= x {}^{2} - px - (p + c)$

$\alpha + \beta = p \\ \alpha \beta = - (p + c)$

according to the question

$( \alpha \beta + (\alpha + \beta) + 1) = 0$

by substituting the values,

we get

$p - p - c + 1 = 0 \\ c = 1$