Question

If alpha, Beta are the zeroes of the polynomials
2x²- 11x +12. then find a polynomial whose
zeroes are 1/alpha and 1/beta.​

Answer 1

Answer:

ID 6692933260 PASWRD 12345

Answer 2

Answer:

Given :

α & β are zeroes of the polynomial 2x² - 11x + 12

To Find :

Value of α²β + αβ²

Solution :

Compare given equation 2x² - 11x + 12 with ax² + bx + c , we get ,

⇒ a = 2 , b = -11 , c = 12

Then ,

Sum of zeroes , α + β = -b/a = 11/2 ... (1)

Product of zeroes , αβ = c/a = 12/2 = 6 ... (2)

Now , our required value,

⇒ α²β + αβ²

⇒ αβ ( α + β ) ... [ From (1) & (2) ]

⇒ 6 ( 11 / 2 )

⇒ 33

Step-by-step explanation: