If alpha beta are the zeroes of the poynomial f(x)=xsquare-5x+k such that alpha - beta =1 find k?
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Hey!
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Question = f(x) = x² - 5x + k
Given :-
α - β = 1
Sum of zero = -(coefficient of x ÷ coefficient of x²)
α + β = -b ÷ a
Product of zero = constant term ÷ coefficient of x²
α.β = c ÷ a
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Now :-
α + β = -(-5) ÷ 1
α.β = K ÷ 1
α - β = 1
α + β = 5
α = 3
β = 2
Now value of K :-
=> α.β = K
=> 3 × 2 = K
=> 6 = K
_____________________________________________________________________________________________
Regards :)
Cybary
Be Brainly
_____________________________________________________________________________________________
Question = f(x) = x² - 5x + k
Given :-
α - β = 1
Sum of zero = -(coefficient of x ÷ coefficient of x²)
α + β = -b ÷ a
Product of zero = constant term ÷ coefficient of x²
α.β = c ÷ a
______________________________________________________________
Now :-
α + β = -(-5) ÷ 1
α.β = K ÷ 1
α - β = 1
α + β = 5
α = 3
β = 2
Now value of K :-
=> α.β = K
=> 3 × 2 = K
=> 6 = K
_____________________________________________________________________________________________
Regards :)
Cybary
Be Brainly
Anonymous:
:)
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