if alpha,beta are the zeroes of x^2-4x+1=0,then I/alpha+1/beta-alpha×beta=
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2
Answer:
- 5
Step-by-step explanation:
Given :
p ( x ) = x² + 4 x + 1 = 0
= > x² + 4 x + 1 = 0
We know :
α + β = - b / a
α . β = c / a
= > α + β = - 4
= > α . β = 1
Now :
( 1 / α + 1 / β ) - α β
= > ( α + β / α β ) - ( α β )
Putting values here we get :
= > ( - 4 / 1 ) - 1
= > - 4 - 1
= > - 5
Therefore , required answer is - 5 .
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