Math, asked by tejarorasimran9658, 1 year ago

If alpha, beta are the zeroes of x2+7x+7.Find the values of 1/alpha+1/beta-2alpha beta.

Please solve this. PLZZZZZZZZZ

Answers

Answered by meetbinduu
95
hope this will help u to understand.
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Answered by SerenaBochenek
139

Answer:

\text{The value of }\frac{1}{\alpha}+\frac{1}{\beta}-2\alpha \beta \text{ is }-15

Step-by-step explanation:

Given that α and β are the zeroes of the polynomial

x^2+7x+7

we have to find the value of  

\frac{1}{\alpha}+\frac{1}{\beta}-2\alpha \beta

The polynomial is x^2+7x+7

By comparing with standard form ax^2+bx+c=0

a=1, b=7 and c=7

\text{Sum of zeroes= }\alpha+\beta=\frac{-b}{a}=-\frac{-7}{1}=-7

\text{Product of zeroes= }\alpha.\beta=\frac{c}{a}=\frac{7}{1}=7

Now,  

\frac{1}{\alpha}+\frac{1}{\beta}-2\alpha \beta

=\frac{\beta+\alpha}{\alpha \beta}-2\alpha \beta

=\frac{-7}{7}-2(7)=-1-14=-15

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