If alpha beta are the zeros of a polynomial such that alpha + beta equal to 6 and alpha beta equal to 4 then write the polynomials
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Answered by
9
Given, α and β are the roots of the required polynomial with
α + β = 6 and αβ = 4
Thus, the required polynomial is
p (x) = x² - (α + β)x + (αβ)
= x² - 6x + 4
Therefore, the required polynomial be
(x² - 6x + 4).
#
Answered by
4
Heya !!!
Sum of zeroes = Alpha + Beta = 6
and,
Product of zeroes = Alpha × Beta = 4
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(6)X + 4
=> X²-6X+4.
HOPE IT WILL HELP YOU....... :-)
Sum of zeroes = Alpha + Beta = 6
and,
Product of zeroes = Alpha × Beta = 4
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(6)X + 4
=> X²-6X+4.
HOPE IT WILL HELP YOU....... :-)
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