Question

If alpha beta are the zeros of polynomial f(x)=x^2-3x+6,then find the value of 1/alpha+1/beta+alpha^2+beta^2-2alpha beta

Answer 1

alpha + beta=3
alpha.beta= 6

1/ alpha + 1/ beta= (alpha + beta)/ alpha beta
= 3/6 = 1/2

alpha^2 + beta^2 = ( alpha+ beta)^2 -2alpha beta
= 9 -2.6
= 9-12
=-3

SO 1/2 -3 -2.6
= 1/2 -3- 12
=( 1-6-24)/2
= -29/2

Answer 2

here is your answer....
thanks..