if alpha, beta are the zeros of polynomial p(x)=x²-5 find the value of 1/alpha, 1/beta
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alpha and beta are the zeros of the polynomial p(x)=x2-5x+2.
x² - 5x + 2
Sum of Zeroes = -b/a
Products of Zeroes = c/a
a = 1 b = -5 c = 2
Zeroes are a & ß
a +3=5
αβ = 2
1/a + 1/3
= (B + a)/aß
= 5/2
1/αβ = 1/2
x² - 5x/2 + 1/2 = 0
=> 2x² - 5x+1=0 where zeroes are 1/a & 1/3
1/a & 1/B = (5 ± √25 - 8)/4
=
(5± √17)/4
3aß =3*2= 6
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Answer:
Let alpha =a , beta = b
a and b are the zeroes of p(x)=x^2-5x+4 ,therefore
a+b= 5…………….(1). and. a.b= 4………………(2)
1/a+1/b-2.a.b=?
=(b+a)/a.b -2.ab. Putting a+b=5 from eqn. (1) and a.b= 4 from eqn. (2)
= 5/4 -2×4
=5/4–8
=-27/4
= -6.75. Answer.
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