Question

If alpha beta are the zeros of the equation 6x2+x_2=0 find alpha by beta +beta by alpha

Answer 1

$\mathfrak{Hola!}$

Equation - 6x²+x-2

So, α+β = $\frac{-1}{6}$

and αβ = 2/6 = 1/3

Now,

$\frac{α}{β}$ +$\frac{β}{α}$

= $\frac{α²+β²}{αβ}$

= (α+β)²-2αβ/αβ

Substituing the values we get

(-1/6)2(1/3)/1/3

= -1/9/1/3

= $\frac{-1}{9}$*3

= -1/3