Question

if alpha , beta are the zeros of the polonomial f(x)= x^2-p(x+1)-c,then what will be the value of (alpha+1)(beta+1).​

Answer 1

Step-by-step explanation:

I cannot write alpha and beta so I am writing a and b

(a+1)(b+1)=a+b+2ab

We know a+b =- coefficient of x/coefficient of constant

So a+b=-p/(p-c)

And ab=coefficient of constant/coefficient of x^2

So ab=p-c hence 2ab=2(p-c)

So the required number is [p/(p-c)]+[2(p-c)]

Please mark me as brainliesy

Answer 2

Answer:

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