if alpha beta are the zeros of the quadratic polynomial 2 x square - 3 x minus 5 form a polynomial whose zeroes are 2 alpha+1 and 2 beta +1
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2x^-5x+2x-5=0
x(2x-5)+1(2x-5)=0
(2x-5) (x+1) =0
x=5/2,-1
2alpha +1= 2×5/2+1=6
2 beta +1 = 2×-1= -2
x^-(6-2)x+(-2)
x^-4x-2=0
x(2x-5)+1(2x-5)=0
(2x-5) (x+1) =0
x=5/2,-1
2alpha +1= 2×5/2+1=6
2 beta +1 = 2×-1= -2
x^-(6-2)x+(-2)
x^-4x-2=0
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