Question

if alpha + beta are the zeros of x square - 6 X + K what is the value of k if 3 alpha + 2 Beta equal to 20​

Answer 1

Answer:

Therefore k = -16.

Step-by-step explanation:

Here we go,

Since

a and b are the roots of this equation,

${x}^{2} - 6x + k = 0$

a+ b = -(-6)/1 -----(i)

and

ab = k ----- (ii)

Now,

3a + 2b = 20

Substituting for b gives,

3a + 12-2a = 20

a + 12 = 20

a = 8

Using this value of a in (i)

8 +b =6

b = -2

Now using these values in (ii) gives,

ab = (8)(-2) = -16 = k