if alpha beta are zeroes is ax2-3(a-1)x-1 find a
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Step-by-step explanation:
The value of a is 1.
Step-by-step explanation:
Given that if 1 is a zero of the polynomial
ax^2-3 (a-1)x-1
we have to find the value of a
As 1 is one of the zero of above polynomial therefore by remainder theorem
P(1)=0
p(1)=0 a (1)^2 - 3(a-1) (1)=0
a-3 (a-1) -1=0
-2a+2=0
2a=2
⇒ a = 1
The value of a is 1.
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