Math, asked by dhanush31082005, 10 months ago

if alpha beta are zeroes of ax2-3(a-1)x-1 find a

Answers

Answered by Anonymous

3

Answer:

p(x) = ax²- 3(a-1)x -1

Given, 1 is its zero

p(x) = a(1)² -3(a-1)1 -1 = 0

a - 3a+3 -1 = 0

-2a + 2 = 0

-2a = -2

a = -2/-2

a = 1

Step-by-step explanation:

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