if alpha beta are zeroes of ax2-3(a-1)x-1 find a
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Answer:
p(x) = ax²- 3(a-1)x -1
Given, 1 is its zero
p(x) = a(1)² -3(a-1)1 -1 = 0
a - 3a+3 -1 = 0
-2a + 2 = 0
-2a = -2
a = -2/-2
a = 1
Step-by-step explanation:
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