If alpha beta are zeroes pf quadratic polynomial x2-6x+a , find th e vaue of a if 3alpha+2 beta =20
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Answered by
1
we know that ,sum of zeroes=
![\alpha + \beta = \frac{ - b}{a} = \frac{6}{1} = 6 \alpha + \beta = \frac{ - b}{a} = \frac{6}{1} = 6](https://tex.z-dn.net/?f=+%5Calpha++%2B++%5Cbeta++%3D++%5Cfrac%7B+-+b%7D%7Ba%7D++%3D++%5Cfrac%7B6%7D%7B1%7D++%3D+6)
__________________________(1)
also , product of zeroes,
![\alpha \beta = \frac{c}{a} = a \alpha \beta = \frac{c}{a} = a](https://tex.z-dn.net/?f=+%5Calpha++%5Cbeta++%3D++%5Cfrac%7Bc%7D%7Ba%7D++%3D+a)
________________________(2)
now...
![3 \alpha + 2 \beta = 20 3 \alpha + 2 \beta = 20](https://tex.z-dn.net/?f=3+%5Calpha++%2B+2+%5Cbeta++%3D+20)
_________________________(3)
multiply 2 to (1) and subtract (1) from (3),
![3 \alpha + 2 \beta = 20 \\ 2\alpha + 2 \beta = \: 12\\......................... \\ \alpha = 8 \\ ............................ 3 \alpha + 2 \beta = 20 \\ 2\alpha + 2 \beta = \: 12\\......................... \\ \alpha = 8 \\ ............................](https://tex.z-dn.net/?f=3+%5Calpha++%2B+2+%5Cbeta++%3D+20+%5C%5C++2%5Calpha++%2B+2+%5Cbeta++%3D+++%5C%3A+12%5C%5C.........................+%5C%5C+%5Calpha++%3D+8+%5C%5C+............................)
from (1),
![\beta = 6 - 8 = - 2 \beta = 6 - 8 = - 2](https://tex.z-dn.net/?f=+%5Cbeta++%3D+6+-+8+%3D++-+2)
from (3),
![\alpha \beta = a \\ \\ a = 8 \times - 2 \\ = - 16 \alpha \beta = a \\ \\ a = 8 \times - 2 \\ = - 16](https://tex.z-dn.net/?f=+%5Calpha++%5Cbeta++%3D+a+%5C%5C++%5C%5C+a+%3D+8+%5Ctimes++-+2+%5C%5C++%3D++-+16)
_________________________________
__________________________(1)
also , product of zeroes,
________________________(2)
now...
_________________________(3)
multiply 2 to (1) and subtract (1) from (3),
from (1),
from (3),
_________________________________
mouni52:
HI ans
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Answer this question plzzz
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Your answer is here ......
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