if alpha, beta are zeros of p(x)= x³-5x+k and alpha - beta= 1 then find k
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Heya !!!
I think there is a mistake in your question.
Polynomial should be P(X) = X²-5X+K
P(X) => X²-5X+K
Here,
A = 1 , B = -5 and C = K
Alpha + Beta = -B/A
Alpha + Beta = -(5)/1
Alpha + Beta = 5 --------(1)
And,
Alpha - Beta = 1 ----------(2)
From equation (1) we get,
Alpha + Beta = 5
Alpha = 5- Beta ---------(3)
Putting the value of Alpha in equation (2)
Alpha - Beta = 1
5 - Beta - Beta = 1
-2Beta = 1-5
-2Beta = -4
Beta = -4/-2 => 2
Putting the value of Beta in equation (3)
Alpha = 5 - Beta
Alpha = 5-2 = 3
Product of zeroes = C/A
Alpha × Beta = K/1
3 × 2 = K /1
K = 6
HOPE IT WILL HELP YOU...... :-)
I think there is a mistake in your question.
Polynomial should be P(X) = X²-5X+K
P(X) => X²-5X+K
Here,
A = 1 , B = -5 and C = K
Alpha + Beta = -B/A
Alpha + Beta = -(5)/1
Alpha + Beta = 5 --------(1)
And,
Alpha - Beta = 1 ----------(2)
From equation (1) we get,
Alpha + Beta = 5
Alpha = 5- Beta ---------(3)
Putting the value of Alpha in equation (2)
Alpha - Beta = 1
5 - Beta - Beta = 1
-2Beta = 1-5
-2Beta = -4
Beta = -4/-2 => 2
Putting the value of Beta in equation (3)
Alpha = 5 - Beta
Alpha = 5-2 = 3
Product of zeroes = C/A
Alpha × Beta = K/1
3 × 2 = K /1
K = 6
HOPE IT WILL HELP YOU...... :-)
pratapanuraglup96ahc:
absolutely right
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