If alpha beta are zeros of the polynomial p(x), then find the polynomial p(x)
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1
Answer:
The given equation is P(x)=x
2
−3x+2k
Comparing with the standard form of quadratic polynomial ax
2
+bx+c=0 we get
a=1,b=−3,c=2k
We know that α=
2a
−b+
D
,β=
2a
−b−
D
, where D=b
2
−4ac
Then we get,
α+β=
a
−b
=
1
−(−3)
α.β=
a
c
=
1
2k
Now, α+β=α.β ...... (Given)
∴3=2k
∴k=
2
3
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