Question

if alpha,beta ,gama are the roots of the equation x³+2x²+3x+6=0 evaluate Σ(alpha³beta)​

Answer 1

Answer:

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Answer 2

Answer:

-7

Step-by-step explanation:

As α,β,γ are roots of x

3

+2x

2

+3x+4=0

α+β+γ=−2

αβ+βγ+γα=3

αβγ=−4

Now ∑α 2 β 2 =(α 2 β 2 +β 2 γ 2 +γ 2 α 2 )

=(α+β+γ) 2−2αβγ(α+β+γ)

=9−2(−2)(−4)=−7