Question

If alpha,beta Gama are the zeroes of the polynomial ax³+bx²+CX+d then find alpha+beta+gama​

Answer 1

Answer:

a,b,c

Step-by-step explanation:

alfa=a

beta=b

gama=c

Answer 2

(alpha)+(beta)+(gama) = -b/a


(alpa)(beta)+(beta)(gama)+(gama)(alpha) = c/a


(alpha)(beta)(gama) = -d/a