If alpha beta gamma are distinct roots of the equation x^3-3x+11
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Answer:
x² - 6x + 9
Step-by-step explanation:
If alpha beta gamma are the roots of the equation x2 - 3x + 11 then find the equation whose roots are (alpha + beta)
α & β are roots of x² - 3x + 11
=> α + β = - (-3)/1 = 3 (Sum of roots)
α + β is roots of other equation
let say γ is roots of other equation
so γ = α + β = 3
Sum of roots = γ + γ = 3 + 3 = 6
Products of roots = γ * γ = 3 * 3 = 9
Equation
x² - 6x + 9
or Simply
(x - γ)(x - γ)
= (x-3)(x-3)
= (x -3)²
= x² - 6x + 9
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