Question

If alpha ,beta,gamma are roots of the equation x^3+3x+1=0,, then [alpha]+[beta]+[gamma] is

Answer 1

I think the answer should be -3....

Answer 2

Answer:

Step-by-step explanation:

x^3+3x+1=0

x^3-0.x^2+3x+1=0

α+β+= -b/a

α+β+= 0/1

α+β+=0

Hope it helps you!......