Question

if alpha, beta, gamma are tge zeroes of the polynomial f(x)=ax^3+bx^2+cx+d, then 1/alpha+1/beta+1/gamma=______​

Answer 1

1/a + 1/b + 1/c = bc + ac + ab /abc

by finding

1) sum of two mulltiple of zero

2) and product of zeros

you can find

1/alpha + 1/beta + 1/gamma =

Answer 2

Answer:

1/a + 1/b + 1/c = bc + ac + ab /abc

by finding

1) sum of two mulltiple of zero

2) and product of zeros

you can find

1/alpha + 1/beta + 1/gamma =

Step-by-step explanation:

Hope this answer will help you.