Question

If alpha , beta, gamma are the zeroes of the polynomial x3-8 then find the value of alpha+beta+gamma

Answer 1

Step-by-step explanation:

1. by trial method find out first zero ,i.e,

put values starting from 1 , -1 ,2 ,-2 ...

taking x=2

(2)^3 - 8 = 0

so x= 2 is first zero ( alpha ).

2. for second root , divide (x^3 - 8) by x-2 .

we get (x^2 + 2x + 4)

now factorise this and get the rest of two roots .