Question

if alpha beta gamma are the zeros of a cubic polynomial P Y is equal to 3y cube + 8y square - 2 y + 7 find the product of the zeros

Answer 1

$\huge{\bold{Hello!!!}}$

Given,

$p(y) = 3y {}^{3} + 8y {}^{2} - 2y + 7$

On comparing with

$ax {}^{3} + bx {}^{2} + cx + d$

, we get

a = 3, b = 8, c = - 2, d = 7

Product of zeroes

$= \alpha \beta \gamma$
$= > \alpha \beta \gamma = \frac{ - d}{a} \\ \\ = > \alpha \beta \gamma = \frac{ - 7}{3}$

$\textbf{Hope it helps!!}$