If alpha, beta, gamma are the zeros of the polynomial x3 + 4x + 1 then (alpha + beta) –1 + (beta + gamma) -1 + (gamma + alpha) -1 =
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Answered by
3
Here,
a=1,b=0,c=4 and d=1
and,
alpha+beta+gama=-b\a=0\1=0
Now,
We have to find,
apha+beta-1+beta+gama-1+gama+alpha-1
=2alpha+2beta+2gama-3
=2(alpha+beta+gama)-3
=2(0)-3
=0-3
=-3
Therefore,
-3 is the answer
a=1,b=0,c=4 and d=1
and,
alpha+beta+gama=-b\a=0\1=0
Now,
We have to find,
apha+beta-1+beta+gama-1+gama+alpha-1
=2alpha+2beta+2gama-3
=2(alpha+beta+gama)-3
=2(0)-3
=0-3
=-3
Therefore,
-3 is the answer
Answered by
0
Answer:
hi answer is -3
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