Question

if alpha,beta,gamma are zeroes of cubic polynomial 6x^3-11x-3x+2,then find alpha beta+beta gama+gama alpha​

Answer 1

Answer:

alpha beta + beta gama + gama alpha = c/a

here, c= -3

a=6

so, c/a

= -3/6

=-1/2

so, alpha beta + beta gama + gama alpha is equals to -1/2

Answer 2

Answer:

alpha+beta+gamma =-1/2