Question

if alpha, beta, gamma are zeroes of the cubic polynomial 6x+3x2-5x+1 find the value of 1/alpha 1/beta 1/gamma

Answer 1

Answer:

$6x {}^{3} + 3x {}^{2} - 5x + 1 \\ \\ \alpha \beta \gamma = \frac{ - 1}{6} \\ \\ \\ \frac{1}{ \alpha \beta \gamma } = - 6$